Direction of the force in Pair interactions

From: Jérôme Hénin (jerome.henin_at_uhp-nancy.fr)
Date: Tue Aug 24 2004 - 03:46:33 CDT

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Hi all,

In the NAMD manual, the section about pair interaction calculations reads "
The displayed force is the force on atoms in group 1". I expect the force
exerted on group 1 to be the opposite of the one exerted on group 2.

However, when I swap the group flags, I obtain exactly the same force vectors,
not the opposite.

Has anyone got an explanation for this?

Thanks,
Jerome

-- 
Jérôme Hénin
Equipe Dynamique des Assemblages Membranaires
Université Henri Poincaré / CNRS    UMR 7565
B.P. 239	54506 Vandoeuvre-lès-Nancy Cedex
Tel : (33) 3 83 68 43 95	Fax : (33) 3 83 68 43 71
http://www.edam.uhp-nancy.fr/

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