Re: rotation constraints

From: Jim Phillips (jim_at_ks.uiuc.edu)
Date: Thu Nov 13 2003 - 15:18:49 CST

Hi,

It's kcal/mol/Angstrom^2, and the potential formula is k*(x-x0)^2, and
therefore the force is -2k(x-x0).

-Jim

On Tue, 11 Nov 2003, himanshu chandola wrote:

> hi everyone,
> does anybody have an idea as to the units of 'k' - the stiffness
> constant in harmonic as well as rotational constraints?
>
> thanks in adnvance,
>
> himanshu
>
> ----------------------------------------
> Morpheus: Do you believe in fate, Neo?
> Neo: No.
> Morpheus: Why Not?
> Neo: Because I don't like the idea that I'm not in control of my life.
>
>

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