Re: SMD and CPT? (fwd)

From: Marcos Sotomayor (sotomayo_at_ks.uiuc.edu)
Date: Fri Feb 09 2007 - 17:22:11 CST

Got it!

Thanks,
Marcos

On Fri, 9 Feb 2007, Sterling Paramore wrote:

> In my notes, H refers to the energy of the system of interest (i.e., not the
> cantilever). The work is then the work that the force does on the system of
> interest. You could also calculate the work done on the total system (system
> of interest + cantilever), by just adding in the potential of the cantilever
> to the hamiltonian. In this case, I get \dot{H} = F_SMD * \dot{R}, where R
> is the equilibrium position of the SMD potential (if modelled harmonically).
> This is the work done on the total system by moving the cantilever
> equilibrium position. It really depends on what you want.
>
> -Sterling
>
>
> Marcos Sotomayor wrote:
>
>>
>> Are you sure you can describe the motion of the system when the SMD force
>> is applied (\dot{H}) without taking into account the external force? I
>> don't understand why you can claim that \dot{H} does not have the term
>> dU_SMD(t)/dt?
>>
>> Marcos
>>
>> On Fri, 9 Feb 2007, Sterling Paramore wrote:
>>
>>> Changed my mind, the work should definitely be F*d. I wrote up a short
>>> proof here:
>>> http://www.cbms.utah.edu/~paramore/smd_work.jpg
>>>
>>> -Sterling
>>>
>>> Sterling Paramore wrote:
>>>
>>>
>

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