From: LEWYN LI (ll2150_at_columbia.edu)
Date: Tue Sep 13 2005 - 15:16:48 CDT
There is an error in your calculation:
2500 kcal/mol * 1000/0.23 = 10460000 N*m/mol
Not 575000 N*m/mol as you have written.
Following all the other steps in your derivation then gave a value
of ~3600 kBT.
On Tue, 13 Sep 2005, paul.dalhaimer_at_yale.edu wrote:
> Try this, Anna:
> 2500 kcal/mol * 1000 / 0.23 = 575000 N*m/mol
> 575000 N*m/mol * 10^9 * 10^12 = 5.75*10^26 pN*nm/mol
> 5.75*10^26 pN*nm/mol * 6.02*10^-23 * #molecules in your system ~ 200
> with 4.2 pN*nm = 1 kBT
> 200 kBT is about the amount of work it takes to unfold RNA or a
> multidomain protein. Please post corrections if you find a mistake
> with my calculation...
> Quoting Anna Modzelewska <amodzelewska_at_iimcb.gov.pl>:
>> I calculated the pair interactions energy between two proteins and I
>> got values about -2500. Is it in kcal/mole?
>> If yes, why these energies are so big? How to correlate them with
>> experimental values?
>> Thank you
This archive was generated by hypermail 2.1.6 : Wed Feb 29 2012 - 15:41:08 CST