# Re: energy values

From: \ (jonathan_at_ibt.unam.mx)
Date: Tue Sep 13 2005 - 13:30:50 CDT

Hello. I think the third line should read
(5.75*10^26 pN*nm/mol)/(6.02*10^23 molecules/mol)*(#molecules in your system)~
200 kBT/molecule * #molecules in your system
5.75*10^26 pN*nm/mol * 6.02*10^-23 * #molecules in your system ~ 200 kBT

It's only a typo, though, since the final numeric result is the same.

J. Valencia

Quoting paul.dalhaimer_at_yale.edu:

> Try this, Anna:
>
> 2500 kcal/mol * 1000 / 0.23 = 575000 N*m/mol
> 575000 N*m/mol * 10^9 * 10^12 = 5.75*10^26 pN*nm/mol
> 5.75*10^26 pN*nm/mol * 6.02*10^-23 * #molecules in your system ~ 200
> kBT
>
> with 4.2 pN*nm = 1 kBT
>
> 200 kBT is about the amount of work it takes to unfold RNA or a
> multidomain protein. Please post corrections if you find a mistake
> with my calculation...
>
>
>
> Quoting Anna Modzelewska <amodzelewska_at_iimcb.gov.pl>:
>
> > Hi,
> > I calculated the pair interactions energy between two proteins and I
> > got values about -2500. Is it in kcal/mole?
> > If yes, why these energies are so big? How to correlate them with
> > experimental values?
> >
> > Thank you
> > Anna
> >
>
>

This archive was generated by hypermail 2.1.6 : Wed Feb 29 2012 - 15:39:55 CST